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Brandin Cooks' new contract with Rams shows exactly why Patriots traded him

Ryan Hannable
July 17, 2018 - 9:13 pm

Brandin Cooks spent just one season in New England.

The wide receiver was traded to the Rams this offseason in a move that wasn't all that surprising considering Bill Belichick has been known to trade players the year before they become free agents so the team can get something in return instead of just seeing them leave via free agency for nothing.

New England received the No. 23 overall pick in April's draft in exchange for Cooks and a fourth-round pick.

Cooks finished last season with 65 catches for 1,028 yards and seven touchdowns.

On Tuesday, Cooks reportedly signed a five-year extension with the Rams worth $81 million and $20.5 million guaranteed. Seeing this figure, it's really no surprise the Patriots traded him when they did.

While Cooks is a good player, there was no chance the Patriots would even come close to giving him that kind of money. Just look at the other two top receivers on the roster -- Julian Edelman is playing with a two-year deal worth $11 million and Chris Hogan is playing with a three-year deal worth $12 million. Those deals aren't even close to the money Cooks got and he isn't that much better than they are, either.

It made a lot of sense for the Patriots to get a player (Isaiah Wynn), who will potentially help the team out for years to come, in exchange for just one more season of Cooks.

Cooks signing such a big deal Tuesday just confirmed why the Patriots dealt him when they did.

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